SOLUTION: Two cans of soda and an order of fries cost $2.60. One can of soda and two orders of fries cost $2.80. What is the cost of a can of soda and of an order of fries?

Question 133215This question is from textbook Amco's Integrated Algebra 1
: Two cans of soda and an order of fries cost $2.60. One can of soda and two orders of fries cost $2.80. What is the cost of a can of soda and of an order of fries? This question is from textbook Amco's Integrated Algebra 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two cans of soda and an order of fries cost $2.60. One can of soda and two orders of fries cost $2.80. What is the cost of a can of soda and of an order of fries?
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Let cost of soda be "x"; Let cost of fries be "f".
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EQUATIONS:
2s + f = 2.60
s +2f = 2.80
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Multiply 1st be 2 to get:
4s + 2f = 5.20
Sutract 2nd from 3rd to get:
3s = 2.40
s = .80 (cost of soda)
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Substitute to solve for "f":
2*0.8 + f = 2.6
1.6 + f = 2.6
f = 1 (cost of fries)
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Cheers,
Stan H.
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