SOLUTION: Please help me to find the vertex form of {{{ Y= -2x^2-16x-32 }}}.

SOLUTION: Please help me to find the vertex form of {{{ Y= -2x^2-16x-32 }}}.

Algebra.Com

Question 132912: Please help me to find the vertex form of .
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the vertex form of .
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2x^2+16x = -(y+32)
2(x^2+8x+16) = -y-32+2*16
2(x+4)^2 = -y
(x+4) = (-1/2)(y-0)
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Vertex: (-4,0)
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Cheers,
Stan H.
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