SOLUTION: The problem 3xy(4+2xy)6xy (to third power) I started within the () which would give me 6xy+4 then 6 to the 3rd is 222xy +4 Did I approach this problem correctly, If not how sho

Algebra ->  Equations -> SOLUTION: The problem 3xy(4+2xy)6xy (to third power) I started within the () which would give me 6xy+4 then 6 to the 3rd is 222xy +4 Did I approach this problem correctly, If not how sho      Log On


   

Question 13269: The problem 3xy(4+2xy)6xy (to third power)
I started within the () which would give me
6xy+4 then 6 to the 3rd is 222xy +4
Did I approach this problem correctly, If not how should I? Thank you Peter Droste grade9 pdroste@stny.rr.com
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not at all sure what your problem is. First off, however, you can't do anything within the parentheses, because they are NOT like terms. Do you mean:

3xy%2A%284%2B2xy%29%2A6xy%5E3+. It still doesn't look exactly like most math problems look. Do you have parentheses anywhere else in this problem that I don't have in this? If indeed this is the case, then let's multiply the 3xy+ times the 6xy%5E3to get 18%28x%5E2%29%2A%28+y%5E4%29.

Next take the 18x%5E2y%5E4 times the remaining factor +%284+%2B+2xy%29+.
18x%5E2y%5E4%284+%2B+2xy%29=+72%28x%5E2%29%2A%28y%5E4%29+%2B+36+%28x%5E3%29%2A%28+y+%5E5%29+

If this is NOT the correct statement of your problem, then resubmit the problem and someone will take a look at it for you!

R^2 at SCC