SOLUTION: two families meet at a park for a picnic. At the end of the day one family travels east at an average speed of 42 mph and the other travels west at an average speed of 50 mph. both
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Question 132514: two families meet at a park for a picnic. At the end of the day one family travels east at an average speed of 42 mph and the other travels west at an average speed of 50 mph. both families have approximately 160 miles to travel.
a)find the time it takes each family to get home
b)find the time that will have elapsed when they are 100 miles appart
c)find the distance the eastbound family has to travel after the westbound family has arrived home.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
At the end of the day one family travels east at an average speed of 42 mph and the other travels west at an average speed of 50 mph. both families have approximately 160 miles to travel.
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a)find the time it takes each family to get home
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East bound DATA:
Rate = 42 mph : distance = 160 miles ; time = 160/42 = 3.81 hrs.
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West bound DATA:
Rate = 50 mph ; distance = 160 miles ; time = 160/50 = 3.2 hrs.
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b)find the time that will have elapsed when they are 100 miles apart
(42+50)x = 100
x = 100/92
x = 1.087 hrs.
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c)find the distance the eastbound family has to travel after the westbound family has arrived home.
3.81-3.2 = 0.61 hr.
0.61 hr * 42 mph = 25.62 miles
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Cheers,
Stan H.
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