You can
put this solution on YOUR website!# 1

Start with the given equation

Subtract

from both sides

Rearrange the equation

Divide both sides by

Break up the fraction

Reduce
So the equation is now in slope-intercept form (

) where the slope is

and the y-intercept is
So to get the equation into function form, simply replace y with f(x)
So the equation changes to the function
Looking at

we can see that the equation is in slope-intercept form

where the slope is

and the y-intercept is
Since

this tells us that the y-intercept is
)
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is

, this means:
which shows us that the rise is -4 and the run is 1. This means that to go from point to point, we can go down 4 and over 1
So starting at
)
, go down 4 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph

So this is the graph of

through the points
)
and
# 2

Start with the given equation

Subtract

from both sides

Rearrange the equation

Divide both sides by

Break up the fraction

Reduce
So the equation is now in slope-intercept form (

) where the slope is

and the y-intercept is
So to get the equation into function form, simply replace y with f(x)
So the equation changes to the function
Looking at

we can see that the equation is in slope-intercept form

where the slope is

and the y-intercept is
Since

this tells us that the y-intercept is
)
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is

, this means:
which shows us that the rise is 2 and the run is 1. This means that to go from point to point, we can go up 2 and over 1
So starting at
)
, go up 2 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph

So this is the graph of

through the points
)
and