SOLUTION: Hi. I'm having trouble with this problem. Can you help me?
Sketch the graph of the given parabola and state the coordinates of its vertex and its intercepts.
y = 2x^2 - 12x +
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Question 127715: Hi. I'm having trouble with this problem. Can you help me?
Sketch the graph of the given parabola and state the coordinates of its vertex and its intercepts.
y = 2x^2 - 12x + 18
( , ) (vertex)
y = (y-intercept)
x = (leftmost x-intercept)
x = (rightmost x-intercept)
Answer by HyperBrain(694) (Show Source): You can put this solution on YOUR website!
Read first the lesson
Shortcut in finding the vertex of any parabola
Ok, done?
Let's start!
Differentiating,
Equating to zero,
Solving for y,
y=0 and x=3 So,
The vertex is at (3,0)
Let's check!
Graph:
Ok, we're correct!
Proceed,
to find the x-intercepts, let us equate y=0,
so,
Factoring,
since this is a perfect square, there is only one x-intercept.
So,
the x-intercept is at (3,0).
CHECK:
Done!
Please watch our video http://www.metacafe.com/watch/1101445/science_avenue/
Power up,
HyperBrain!
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