SOLUTION: Hi Can I have some help concerning functions? A quadratic function is given. f(x) = 6x^2 + x + 1 (a) Express the quadratic function in standard form. f(x) = a(x - h)^2 + k

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Question 127713: Hi Can I have some help concerning functions?
A quadratic function is given.
f(x) = 6x^2 + x + 1
(a) Express the quadratic function in standard form.
f(x) = a(x - h)^2 + k where
a =
h =
k =

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation


Subtract from both sides


Factor out the leading coefficient


Take half of the x coefficient to get (ie ).

Now square to get (ie )




Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation



Now factor to get


Distribute


Multiply


Now add to both sides to isolate y


Combine like terms



Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and "a" is the stretch/compression factor. Also "a" tells us which direction the parabola opens.



So in this case the vertex is (,) and the parabola opens upward since


Check:

Notice if we graph the original equation we get:

Graph of . Notice how the vertex is (,).


Notice if we graph the final equation we get:

Graph of . Notice how the vertex is also (,).


So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.


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