SOLUTION: Hi Can I have some help concerning this problem? Sketch the graph of the given parabola and state the coordinates of its vertex and its intercepts. y = 6x^2 + 7x + 1 (v

Question 127701: Hi Can I have some help concerning this problem?
Sketch the graph of the given parabola and state the coordinates of its vertex and its intercepts.
y = 6x^2 + 7x + 1
(vertex)
y = (y-intercept)
x = (leftmost x-intercept)
x = (rightmost x-intercept)
Answer by JessicaGill(40) (Show Source): You can put this solution on YOUR website!
Using the quadratic solver here are the steps

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=25 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -0.166666666666667, -1. Here's your graph:

You can also use the vertex formula to find the x coordinate of the vertex and the axis of symmetry. Once you find the x value, substitute the value for x in the original equation and find the y coordinate of the vertex.
Then choose two x values either two the left or the right of the vertex and sustitute and solve for the y coordinates to the x values.
Then graph the reflection of each of those points and graph the parabola points and sketch the graph. You will have to estimate the points from the graph above.
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