SOLUTION: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE
Algebra.Com
Question 126231: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE THE TWO WILL MEET IF THE HOUSES ARE 4 MILES APART?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
First think about what is generally true. They meet
somewhere in the middle, so the sum of their walks
is 4 miles. They leave at the same time, so the
time each spends walking is exactly the same.
Now you can start
Let = distance in miles Fred walks
Let = distance in miles Jon walks
what I just said
Let = time in hours they both spend walking
Now add these equations
hr
or
They will meet in minutes answer
RELATED QUESTIONS
Fred begins walking toward's John's house at 3 mi/h. John leaves his house at the same... (answered by chessace)
fred begins walking toward johns house at 3 mi/h. john leaves his house at the same time (answered by BurningFlame_marc)
Fred begins walking toward John's house at 3 mi/h. John leaves his house at the same... (answered by scott8148)
Mike and Jon leave their homes at the same time and meet somewhere in between their... (answered by mananth)
Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same... (answered by TimothyLamb)
Write and solve an equation for each situation:
3. May rides her bike the same... (answered by ankor@dixie-net.com)
Fred begins to walk toward John's house at 3 mph. John leaves his house at the same time... (answered by checkley77)
Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same... (answered by Stitch,richwmiller)
Steve begins walking towards kevins house at 3 mph. Kevin leaves his house at the same... (answered by richwmiller,lwsshak3)