SOLUTION: I need some help, can somebody help me? (-1/8x^7)(-1/9x) Thanks

SOLUTION: I need some help, can somebody help me? (-1/8x^7)(-1/9x) Thanks

Algebra.Com

Question 124431: I need some help, can somebody help me?

(-1/8x^7)(-1/9x)
Thanks
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(-1/8X^7)(-1/9X)=1/72X^8
OR:
(-1/8)X^7*(-1/9)X=X^8/72
RELATED QUESTIONS
Hello! I need help please. log (10,000)=? Can somebody help me?... (answered by nerdybill)

i really need help......please somebody help me 5n+1 divided by 8 =1/2 (answered by pwac)

Can somebody please help me? Solve by substitution. 8x-4y=16 y=2x-4... (answered by checkley75)

I need help solving these two seperate problems by using the substitution method. Can... (answered by solver91311)

I need some help Solve the following equations by factoring or by any of the... (answered by mathispowerful)

Can someone help me on this? I need to subtract: 7/9 - 1/6 Thanks,... (answered by checkley71)

5/4x+1/8x=3/8+x Can I please have some one help... (answered by neatmath)

I need some help on this problem, can someone help me? sqrt of 9x+25/81 (answered by Alan3354)

Can somebody please help me with this proof that I am stuck on? I need to solve it by... (answered by fcabanski)