Let "t" be the time (in hours) for car A moving from S to LA to get the meeting moment. Then the time for car B moving from LA to S is (t-1) hours to get the meeting point (one hour less). The time equation for the meeting moment t is 60t + 75*(t-1) = 400 miles (the whole route length). Simplify and find t from this equation 60t + 75t - 75 = 400 60t + 75t = 400 + 75 135t = 475 t = 475/135 = 3.518519 hours. So, the time for the car B moving from LA to the meeting point is one hour less than that, i.e. 2.518519 hours. The distance from LA to the meeting point is 75*2.518519 = 188.888925 miles. It is 188.888925 -150 miles = 38.888925 miles from Fresno, between Fresno and Sacramento. ANSWER. The meeting point is 38.9 miles from Fresno, between Fresno and Sacramento.
Car A starts in Sacramento at 11am. It travels along a 400 mile route to Los Angeles at 60 mph. Car B starts from Los Angeles at noon... So Car A is alreadymiles toward Los Angeles when car B starts. So at noon, when car B starts, they are miles apart. Car B starts from Los Angeles and travels to Sacramento along the same route at 75 mph. So their approach rate is mph, so their 340 miles of separation will shrink to 0, i.e., they will meet in hours after noon and when car B is miles from Los Angeles. The route goes past Fresno which is 150 miles along the route from Los Angeles. How far from Fresno are the cars when they meet? So they are 150 miles closer to Fresno than they are to Los Angeles by miles. So the answer is miles from Fresno. Edwin