SOLUTION: If 3+2i is a solution for x^2+mx+n=0, where m and n are real numbers, what is the value of m?

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Question 120366: If 3+2i is a solution for x^2+mx+n=0, where m and n are real numbers, what is the value of m?
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
If is a solution, this means



Start with the given equation



Subtract 3 from both sides


Divide both sides by 2 to isolate "i"


Replace i with . Remember


Square both sides



Distribute the exponent



Square 2 to get 4



Rearrange the terms


Add 1 to both sides



Foil


Distribute


Combine like terms



Multiply both sides by the LCD 4 to eliminate any fractions


Distribute. Notice how the fractions have been eliminated.



So the quadratic that has the solution is


Since m is the coefficient for the x term in , this means and that


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Answer:

So the value of m is




Check:

You can check your answer by using the quadratic formula

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