SOLUTION: Find the general form of the equation of a line passing through the point (1,-2) and perpendicular to the line x+3y-6=0.

Question 1202526: Find the general form of the equation of a line passing through the point (1,-2) and perpendicular to the line x+3y-6=0.

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
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passing through the point (1,-2) and perpendicular to the line x+3y-6=0.
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Perpendicularity of the two lines means that this other line should be either , or .

Pick one of those and then substitute for the given required point and simplify.

----------------OR .
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