SOLUTION: When solving an equation with variables in denominators, we must determine the values that cause these denominators to equal 0, so that we can reject these values if they appear as

Question 1201293: When solving an equation with variables in denominators, we must determine the values that cause these denominators to equal 0, so that we can reject these values if they appear as proposed solutions. Find all values for which at least one denominator is equal to 0. Write answers using the symbol Do not solve.
\frac{-1}{\left(x+3\right)\left(x-4\right)}=\frac{1}{2\left(x+1\right)}
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
\frac{-1}{\left(x+3\right)\left(x-4\right)}=\frac{1}{2\left(x+1\right)}
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Gibberish.
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
If you trying to use LaTeX, that does not render here.

In pure text, (-1)/((x+3)(x-4))=(1)/(2(x+1))

Inside the triple braces tag,
Values which would make any of the denominators zero,
-1, -3, +4
Those x values are rejected but trying to solve the equation,...
.
.
.

(Result was not rechecked.)
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