SOLUTION: Given 3x² - mx + 3 = 0, What values of m would the roots not be real ?

Question 1201074: Given 3x² - mx + 3 = 0, What values of m would the roots not be real ?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
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Form the discriminant of the quadratic equation

    d = b^2 - 4ac = (-m)^2 - 4*3*3 = m^2 - 36


and analyze when the discriminant is negative

    d < 0  <-->  m^2-36 < 0  <-->  m^2 < 36  <-->  -6 < m < 6.


ANSWER.  If  -6 < m < 6, the roots of the equation are not real.

Solved.

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