SOLUTION: Find an equation of the line containing the centers of the 2 circles x^2 + y^2 - 4x + 6y + 4 = 0 and x^2 + y^2 + 6x + 4y + 9 = 0.

Question 1200537: Find an equation of the line containing the centers of the 2 circles
x^2 + y^2 - 4x + 6y + 4 = 0 and x^2 + y^2 + 6x + 4y + 9 = 0.

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Put each circle's equation into standard form, using Completing-The-Square, if necessary. Read the center point of each circle from the standard form equations. Now you would have the two points for the equation of the line you want to find.

The two circle equations are
(x-2)^2+(y+3)^2=9 showing center at (2,-3)
and
(x+3)^2+(y+2)^2=4 showing center at (-3,-2).

You should be able to do the rest, now havig the two required points for the line.

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Either or .
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