SOLUTION:
Two cyclists, 79 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cycli
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Question 120040:
Two cyclists, 79 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cyclist traveling?
_____mi/hr(slower cyclist)
_____mi/hr(faster cyclist)
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X+2X=79
3X=79
X=79/3
X=26.33 MPH FOR THE SLOWEST BIKER.
2*26.33=52.67 MPH FOR THE FASTER BIKER.
PROOF
26.33+52.67=79
79=79
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