I need your help desperately.
1. Consider the following equation,
n(7x-3) = 21x+5.
For what value of n will the equation result in no solution?
2. Consider the following equation,
n(3x+2) = -9x-6.
For what value of n will the equation result in infinitely many solutions?
Please, help me with these questions. Explain in detail.
Thank you.
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(1) Equation (1) has no solution if and only if n= 3.
Indeed, if n= 3, then the equation takes the form
3*(7x-3) = 21x - 5
or, equivalently,
21x - 9 = 21x - 5.
The last equation, OBVIOUSLY, has no solution; otherwise, -9 = -5, which is absurd.
Part (1) is complete.
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Part (2) is very similar. Try to solve it on your own.
You may report me your answer for part (2) - I will check it.
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Comment from student: My work for part 2. n(3x + 2) = -9x - 6 3nx + 2n = -9x - 6
If n = -3, we get the following: -9x - 6 = -9x - 6 So, when n = -3, the equation has an infinite amount of solutions.
Is this right? I need to know tonight. Thanks.
My response. Your work is correct. Everything is RIGHT.
Glad to see your perfect work.
Keep going.
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I also got your another comment, posted before your last comment.
These comments are so different by the tone, that I could not believe
that they are written by the same person.