It takes Calvin 2 hours longer to complete the promotional logo for a male business entrepreneur than it takes Francesca. The two of them work together for 3 hours then Francesca left, and Calvin finished the job in 1 hour. How long would it take each of them, working alone, to finish the job?
Let time Francesca takes to do the job, alone, be F
Then time Calvin takes to do the job, alone, is F + 2
So, Franxesca can do of job in 1 hour, while Calvin can do of job in 1 hour
Together, they can do of job in 1 hour
Since they both worked for 3 hours before Calvin completed the unfinished work in 1 hour, we get the following equation
for the entire JOB:
3(F + 2) + 4F = F(F + 2) ----- Multiplying by LCD, F(F + 2)
0 = (F - 6)(F + 1)
F - 6 = 0 OR F + 1 = 0
Time Francesca takes to do the job, alone, or F = 6 hours
Time Calvin takes to do the job, alone: F + 2 = 6 + 2 = 8 hours