The formula describes the arithmetic progression with the first term of 9
and the common difference of 2.
Therefore, f(6) is the 6th term of this progression
f(6) = 9 + 5*2 = 9 + 10 = 19. ANSWER
Good joking Math problem.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website! If f(1)=9 and f(n)=f(n-1)+2 then find the value of f(6)
f(2) = 9 + 2 = 11
f(3) = 11 + 2 = 13
f(4) = 13 + 2 = 15
f(5) = 15 + 2 = 17
f(6) = 17 + 2 = 19
OR
as previously stated:
Arithmetic Series: d = 2
f(n) = 9 + (n-1)2