SOLUTION:
Science and medicine. A passenger train can travel 325 mi in the same time a
freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h
faster than
Algebra.Com
Question 119379:
Science and medicine. A passenger train can travel 325 mi in the same time a
freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h
faster than the speed of the freight train, find the speed of each.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
seeing as the times are the same we have the following equation
325/(r+25)=200/r cross multiplying we get:
325r=200(r+25)
325r=200r+5000
325r-200r=5000
125r=5000
r=5000/25
r=40 mph for the slower train.
40+25=65 for the faster train.
proof
325/65=200/40
5=5
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