SOLUTION: solve cos2x-2sinx-cos^2 x = -3 on the interval x ∈ [0,2π]
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Question 1192743: solve cos2x-2sinx-cos^2 x = -3 on the interval x ∈ [0,2π]
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
on the interval ∈ [,]
since , we have
periodicity of sin is
general solution:
on the interval ∈ [,] :
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