SOLUTION: Find the values of a, b, and c for which the quadratic equation ax^2+bx+c=0 has the solutions 5-√26 and 5+ √26.
(Hint: Use the zero-product property in reverse.)
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Question 1192005: Find the values of a, b, and c for which the quadratic equation ax^2+bx+c=0 has the solutions 5-√26 and 5+ √26.
(Hint: Use the zero-product property in reverse.)
a=
b=
c=
(Type an integer or a simplified faction.)
Thank you so much for your help!(:
Found 2 solutions by math_tutor2020, greenestamps:
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
I'll use a different approach instead of the hint given.
If you prefer the hint route, then let me know and I'll fix my solution.
and are the two given roots or x intercepts.
For each equation, subtract 5 from both sides
and
If we square both sides, then each right hand side yields 26.
The squaring operation and square root cancel out.
So we have this equation
Let's get it into standard form ax^2+bx+c = 0
Comparing this to ax^2+bx+c = 0, we have
a = 1
b = -10
c = -1
To verify the answers, let's use the quadratic formula to plug in those a,b,c values
We should get the roots your teacher gave you
or
We've confirmed the answers.
Answers:
a = 1
b = -10
c = -1
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
We can assume at the start that a=1; if that leads to values of b and/or c that are not integers, we can scale up our answer.
If a is 1, then b is the opposite of the sum of the roots, and c is the product of the roots.
The sum of the roots is 10.
The product of the roots is 25-26=-1.
ANSWERS:
a=1
b=-10
c=-1
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