SOLUTION: In what bases b, does (b+8) divide into (7b+8) with no remainder?

Question 1191595: In what bases b, does (b+8) divide into (7b+8) with no remainder?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In what bases b, does (b+8) divide into (7b+8) with no remainder?
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Base 4 is one --> 12 & 36.
Base 8 ----> 16 & 64
Base 16 ---> 24 & 120.
Base 40 ---> 48 & 288
That's all.
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I doubt there's an algebraic solution to this.
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