SOLUTION: What is the value of c in the standard form of the equation -2(3x-1)(3x+1)=0?

Question 1184581: What is the value of c in the standard form of the equation -2(3x-1)(3x+1)=0?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

Now you compare this to .
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

The standard form of a quadratic equation ONLY defines the form of the equation,
but DOES NOT DEFINE the values of the coefficients.

The values of the coefficients can be all multiplied by any non-zero coefficient, leaving the equation EQIVALENT;
THEREFORE, the values of the coefficients in the standard form quadratic equation are defined only accurate to the common non-zero multiplier.

Therefore, all your attempts to "invent" a new class of Algebra problems are empty and make no sense.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

The responses from tutor @ikleyn about this series of problem you have posted are right. Although virtually all references will call the standard form of a quadratic function

y=ax^2+bx+c

you can't just post a quadratic expression or equation and ask for the value of a, or the value of b, or the value of c.

So your posts are indeed defective.

However, your questions can be answered IF we assume you are talking about

y=ax^2+bx+c

as the standard form.

And to find the answers to your posts, it is usually NOT necessary to expand the entire expression. In fact, in doing that, the other tutor lost one of the factors of the given expression and so came up with the wrong answer.

For this problem, where you ask for the value of c (the constant term), we only need to multiply the constant factor and the constant terms in the two binomial factors:

c=(-2)(-1)(1) = 2

ANSWER: a=2

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