SOLUTION: For this problem A is the amount of salt in the tank. If a tank contains 250 liters of liquid with 11 grams of salt. A mixture containing 11 grams per liter is pumped into the tan

Question 1184506: For this problem A is the amount of salt in the tank.
If a tank contains 250 liters of liquid with 11 grams of salt. A mixture containing 11 grams per liter is pumped into the tank at a rate of 5 liters/minute. The mixture is well-mixed, and pumped out at a rate of 6 liters/minute. The amount of salt in the tank satisfies the differential equation.
((6A)/(250-t))-55+A'=0
Rewriting this as a linear differential equation we get A'+((6A)/(250-t))=55
A)The integrating factor is
B)And the solution is

Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!

(A) The integrating factor is =

(B) The solution is
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