SOLUTION: The function y = ax^3 + bx^2 + cx + d has a maximum turning point at (−2, 27) and a minimum turning point at (1, 0).
Find the values of a, b, c and d.
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Question 1182759: The function y = ax^3 + bx^2 + cx + d has a maximum turning point at (−2, 27) and a minimum turning point at (1, 0).
Find the values of a, b, c and d.
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
If )
is a point on the function
\ =\ ax^3\ +\ bx^2\ +\ cx\ +\ d)
Then
\ =\ -8a\ +\ 4b\ -\ 2c\ +\ d\ =\ 27)
Similarly,
\ =\ a\ +\ b\ +\ c\ +\ d\ =\ 0)
At the turning points, the first derivative must equal zero, so:
\ =\ 3a(-2)^2\ +\ 2b(-2)\ +\ c\ =\ 0)
and
\ =\ 3a(1)^2\ +\ 2b(1)\ +\ c\ =\ 0)
Solve the 4X4 system for 
John
My calculator said it, I believe it, that settles it
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