SOLUTION: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x � 6y = 9 and passing through (-2, -1)

Question 118275: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x � 6y = 9 and passing through (-2, -1)
Answer by ilana(307) (Show Source): You can put this solution on YOUR website!
First we need to find the slope of the given line, so we could find the slope of the line perpendicular to that. Since 3x - 6y = 9, we could subtract 3x from both sides, giving -6y = -3x + 9. Now divide everything by -6y to get y=(1/2)x-(3/2). Since this is the form y=mx+b, the slope is 1/2. So the line perpendicular has a slope -2. Since it passes through (-2, -1), we can write the equation in point-slope form as y+1=-2(x+2). But we need this in standard form, Ax+By+C=0:
y + 1 = -2x - 4
2x + y + 5 = 0
These coefficients are all integers, so we are done:)
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