SOLUTION: Find the tangent to each curve at the point where t = 3: x = 5(t)^2, y = 10t answer is y = (1/3)x + 15

SOLUTION: Find the tangent to each curve at the point where t = 3: x = 5(t)^2, y = 10t answer is y = (1/3)x + 15

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Question 1180307: Find the tangent to each curve at the point where t = 3:
x = 5(t)^2, y = 10t

answer is y = (1/3)x + 15
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

The point of tangency is (x(3),y(3)) = (45,30)

The slope of the tangent is the derivative of the curve at t=3.

So at t=3 the slope is 1/3.

Use basic algebra with a slope of 1/3 and a point (45,30) to confirm the correctness of the answer you show.

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