SOLUTION: Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number
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Question 1178235: Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number
Found 3 solutions by ikleyn, josgarithmetic, greenestamps:
Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
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Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82.
Find the number
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Do not write "her own son".
The mother can not have a son, who is not "her own son".
. . . Do not frighten people who read your post . . .
Use the punctuation signs properly.
Also, which number you suppose to find ?
The number of stars in the sky ?
/////////////
By writing inaccurately, you deprive yourself of the opportunity to get the solution and explanations from qualified tutors . . .
If you will write in this mode, the tutors who respect themselves, will not communicate with you.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
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Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number
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Which number?
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Five years ago, a mother was twice as old as her son. In 6 years time, the sum of their age will be 82. Find the current age of each.
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--------this is the description. Do what you need to.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Given that the mother was twice as old as her son 5 years ago, I would set up the problem using
x = son's age 5 years ago
2x = mother's age 5 years ago
6 years from now is 11 years after 5 years ago, so....
x+11 = son's age 6 years from now
2x+11 = mother's age 6 years from now
The sum of their ages 6 years from now is 82:
Their ages 5 years ago were 20 and 40.
Their ages now are 25 and 45.
Their ages 6 years from now will be 31 and 51.
It's not clear from your post which "number" you wanted....
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