SOLUTION: % 51 of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confi
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Question 1171376: % 51 of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
(a) P(5) =
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
a. exactly 5 is 10C5*0.51^5*0.49^5=0.2456 also 2ndVARSbinompdf(10,0.51,5)ENTER
b. at least 6 is for 6 through 10=0.4018 1-2ndVARSbinomcdf(10,0.51,5)ENTER, since calculator does binomial from the left, have to subtract the left side from 1 to get the right side
c. fewer than 4 is 0.1560
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