SOLUTION: solve for 'x' b^2x^2+a^2y^2=a^2b^2

Algebra.Com
Question 116976: solve for 'x'
b^2x^2+a^2y^2=a^2b^2

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation



Subtract a^2y^2 from both sides


Divide both sides by


Take the square root of both sides



Simplify



Factor out



Simplify

RELATED QUESTIONS

a(3tx-2b)= c(dx-2) solve for x. (answered by CubeyThePenguin)
solve for x: 1) a(x-3)+8=b(x-1) 2) a(3tx-2b)=c(dx-2) (answered by stanbon)
method of usbstitution 1:a=5-2b 5a+2b=1 2: 2m+n=0 m+2n=3 3: x+y=4 2x-y=5 4:... (answered by Alan3354,ewatrrr)
What are the zeroes of this polynomial if b = -2: f(x) = x^2 + 2x + 2b + bx? a. x =... (answered by jim_thompson5910)
I need help with this Algebra problem, please. Solve the quadratic formula. Simplify... (answered by solver91311)
please i have a problem with the following equation and don't know how to go about it and (answered by ewatrrr)
Solve for x, {{{((a-x)/(a-b))-2=(c-x)/(b-c)}}}. Here's my working, if you could correct... (answered by god2012,nerdybill)
solve for b... (answered by Fombitz)
2A + B + 2C = 1 3A + 2B - C = 2 solve for A B and... (answered by 303795)