SOLUTION: Have I simplified the below problem corectly? 16x^2 -1 over Y^2 divided by 4x + 1 over y^3 = 4xy Thank you

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Question 1169452: Have I simplified the below problem corectly?
16x^2 -1 over Y^2 divided by 4x + 1 over y^3 = 4xy
Thank you

Found 2 solutions by Edwin McCravy, Theo:
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!

Not quite. You lost a term.



Invert the second fraction and change division to multiplication:













Edwin

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
let me see ....

(16x^2-1)/(y^2) / (4x+1)/y^3) is equal to .....

(16x^2-1)/(y^2) * (y^3)/(4x+1) which is equal to .....

(4x-1)*(4x+1)/y^2 * (y^3)/(4x+1) which is equal to .....

y^3/y^2 * (4x-1)*(4x+1)/(4x+1).

y^3/y^2 = y
(4x+1)/(4x+1) = 1

equation becomes:

y * (4x-1) 4xy - y.

you seem to be missing a y somewhere.

to confirm, let y = a random value and x = a random value.
i chose y = 7 and x = 3

((16x^2-1)/y^2) / ((4x+1)/y^3) = 77

4xy = 84

4xy-y = 77

this is easier to see what happens on a manually derived worksheet.

here's my worksheet.




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