SOLUTION: Have I simplified the below problem corectly? 16x^2 -1 over Y^2 divided by 4x + 1 over y^3 = 4xy Thank you
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Question 1169452
:
Have I simplified the below problem corectly?
16x^2 -1 over Y^2 divided by 4x + 1 over y^3 = 4xy
Thank you
Found 2 solutions by
Edwin McCravy, Theo
:
Answer by
Edwin McCravy(20054)
(
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): You can
put this solution on YOUR website!
Not quite. You lost a term.
Invert the second fraction and change division to multiplication:
Edwin
Answer by
Theo(13342)
(
Show Source
): You can
put this solution on YOUR website!
let me see ....
(16x^2-1)/(y^2) / (4x+1)/y^3) is equal to .....
(16x^2-1)/(y^2) * (y^3)/(4x+1) which is equal to .....
(4x-1)*(4x+1)/y^2 * (y^3)/(4x+1) which is equal to .....
y^3/y^2 * (4x-1)*(4x+1)/(4x+1).
y^3/y^2 = y
(4x+1)/(4x+1) = 1
equation becomes:
y * (4x-1) 4xy - y.
you seem to be missing a y somewhere.
to confirm, let y = a random value and x = a random value.
i chose y = 7 and x = 3
((16x^2-1)/y^2) / ((4x+1)/y^3) = 77
4xy = 84
4xy-y = 77
this is easier to see what happens on a manually derived worksheet.
here's my worksheet.
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