SOLUTION: Please help! Find four consecutive integers such that 5 times the opposite of the first is 5 greater than the product of -3 and the sum of the third and fourth. Thanks.

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Question 1165568: Please help!
Find four consecutive integers such that 5 times the opposite of the first is 5 greater than the product of -3 and the sum of the third and fourth.
Thanks.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!



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-----------and you can finish from this.
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Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Please help!
Find four consecutive integers such that 5 times the opposite of the first is 5 greater than the product of -3 and the sum of the third and fourth.
Thanks.
Let first number be F
Then 2nd, 3rd, and 4th are: F + 1, F + 2, and F + 3, respectively
We then get: 5(- F) = - 3(F + 2 + F + 3) + 5
- 5F = - 3(2F + 5) + 5
- 5F = - 6F - 15 + 5
- 5F = - 6F - 10
- 5F + 6F = - 10
First number or
You should now be able to find the other 3!
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