given f(x) = {x^2 -3 for x > 4 {log(x-3) for x <= 4, evaluate f(4)~~~~~~~~~~~~~~~
The value of 4 belongs to the set {x <= 4} and does not belong to the set {x > 4}. Right ? Do you understand it ? But of course ! --- It is OBVIOIUS (!) Therefore, you should use the FIRST line of the two that define the function. So, substitute x= 4 into the formula in the first line of the definition. You will get then f(x) = log(4-3) = log(1) = 0. ANSWER