SOLUTION: The sum of the ages of two brothers is 38 years 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages.

Question 1163142: The sum of the ages of two brothers is 38 years 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The sum of the ages of two brothers is 38 years. 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages.
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e + y = 38 now
4 years ago, e + y = 30
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e + y = 30
e = y^2
---> 5 & 25 then
9 & 29 now
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The hard way:
e + y = 30
e = y^2
y^2 + y - 30 = 0
(y+6)*(y-5) = 0
y = 5
etc
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