SOLUTION: A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour fast

Question 1162610: A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

SPEED TIME DIST. RODE r+10 12/(r+10) 12 WALK r 8/r 8 Total 5

You know what to do,...
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

If you read the problem attentively and then think 30 seconds after reading, you may GUESS the solution MENTALLY: 12 mph cycling and 2 mph hiking. ANSWER If you still prefer algebra solution, then write this "time" equation + = 5 hours, where x is the rate hiking. To solve this equation, multiply both sides by x*(x+10) and then reduce this equation to the standard quadratic equation form. Then solve EITHER via quadratic formula OR factoring. CHECK. + = 1 + 4 = 5 hours.

Solved.

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Using "time" equation is a STANDARD method of solving such problems.
From this lesson, learn on how to write, how to use and how to solve a "time" equation.

To see many other similar solved problems, look into the lessons
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    - Time equation: HOW TO use, HOW TO write and HOW TO solve it
in this site.

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