.
Let x be the amount of the 50% silver alloy, in kilograms.
Then the amount of the 25% silver alloy is (40-x) kilograms.
The pure silver amount in ingredients is 0.5*x + 0.25*(40-x) kilograms.
The pure silver amount in 40 kilograms of the 40% alloy is 0.4*40 = 16 kilograms.
It gives you this equation
0.5x + 0.25*(40-x) = 16.
From the equation
x = = = 24 kilograms.
ANSWER. 24 kilograms of the 50% silver alloy should be mixed with (40-24) = 16 kilograms of the 25% silver alloy.
Solved.
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It is a standard and typical problem on mixtures. See the lessons
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
- Word problems on mixtures for dry substances like candies, dried fruits
- Word problems on mixtures for dry substances like soil and sand
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
- Advanced mixture problems
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.