SOLUTION: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?

SOLUTION: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?

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Question 1161924: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Your equation, as written, does not have two solutions. It is a linear equation with one solution, namely

.

That is because √(2x^2) means

which is equal to

making your equation:

So if you meant for your equation to actually be quadratic, then the first term has to be √2(x^2) which means

Repost your question and tell us what you really mean

John

My calculator said it, I believe it, that settles it

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