SOLUTION: Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is
58.
Algebra.Com
Question 1160303: Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is
58.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 58.
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(n-2) + 2n + 3(n+2) = 58
etc
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