SOLUTION: Write the equation of a line that goes through the point (4, -3) and is perpendicular to the line x−4y=16

Question 1157269: Write the equation of a line that goes through the point (4, -3) and is perpendicular to the line x−4y=16
Found 2 solutions by Boreal, MathLover1:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x-4y=16 can be written as 4y+16=x or 4y=x-16 or y=(1/4)x-4
the slope of that line is 1/4
perpendicular lines have negative reciprocal slopes when multiplied together, so the line wanted has slope -4.
it goes through (4, -3)
point slope formula y-y1=m(x-x1), m slope (x1, y1) point
y+3=-4(x-4)
y=-4x+13

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

the equation of a line that goes through the point (, ) and is perpendicular to the line
perpendicular lines have slopes negative reciprocal to each other
so, first find a slope of given line:
.......solve for

=> a slope is
then negative reciprocal is
=>perpendicular line have slope

so far, the equation of a line will be

...........use iven point (, ) to calculate

and, your equation is:

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