SOLUTION: 19. I need help graphing the following and listing the directions,vertex,axis of symmetry,table with 5 points and the graph for this equation f(x)=(x-6)^2+2

Question 1157012: 19.

I need help graphing the following and listing the directions,vertex,axis of symmetry,table with 5 points and the graph for this equation
f(x)=(x-6)^2+2
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
y=(x-6)^2+2
vertex is h, k so reverse th number in parentheses and use the constant at the end for y.
vertex is (6, 2)
axis of symmetry is the x value or x=2
directrix is found by writing in form (x-h)^2=4p(y-k) so here (x-6)^2=y-2
4p=1'p=1/4
directrix is y=k-p or 2-1/4=7/4
5 points
one is vertex
pick x=0 where y=38
pick x=5 where y=3
because 7 is 1 units away from 6 and 5 is one unit away from 6 they have the same value of y or 3
and if 0 is 6 units away and 12 is 6 units away, they have the same y value of 38

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