SOLUTION: (x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y? A.8 B.10 C.17 D.24

Question 1156649: (x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y?
A.8 B.10 C.17 D.24

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
(x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y?
A.8 B.10 C.17 D.24
~~~~~~~~~~~~~~~~~

Answering formally, NO ONE of the values from the list is valid.

The GLOBAL reason is that the formula written in the post is INCORRECT // absurdist.

In the formula, its left side is IDENTICALLY equal to 0 (zero, ZERO),
while the right side has a constant non-zero value.

Try again, and be MORE ATTENTIVE next time . . .

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