SOLUTION: If y varies as directly as the square of x , and y =75/8 when x =5 ,find y when x =2

Question 1155913: If y varies as directly as the square of x , and y =75/8 when x =5 ,find y when x =2
Found 3 solutions by Theo, MathTherapy, josgarithmetic:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
the direct variation formula is y = kx
y = 75/8 when x = 5
formula becomes 75/8 = k * 5
divide both sides of this equation by 5 to get:
k = (75/8) / 5
solve for k to get:
k = 75/40 = 1.875
k is the constant of variation.
it stays the same regardless of the value of x, with y being dependent on both the value of k and the value of x.
when x = 2, the formula becomes y = 1.875 * 2
solve for y to get y = 3.75
when x = 2, y = 3.75
that's your solution.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
If y varies as directly as the square of x , and y =75/8 when x =5 ,find y when x =2

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
y varies as directly as the square of x ,

y =75/8 when x =5,

The model equation is .

find y when x =2.

, .
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