SOLUTION: A particle moves in a straight line so that its velocity v m/s is given by v=9-t^2,where t is the time in seconds, measured from the start of the motion.Find (a) the value of t a

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Question 1154439: A particle moves in a straight line so that its velocity v m/s is given by v=9-t^2,where t is the time in seconds, measured from the start of the motion.Find
(a) the value of t at which the particle is instantaneously at rest.
(b)the value of t and the speed when the particle is again at its starting point.
(c)the total distance traveled when the particle returns to its starting point.

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

All these questions relate to Calculus.

(a)  The particle is instantaneously in rest when its velocity is equal to zero

         v = 0,   i.e.   9 - t^2 = 0.


      It means  t^2 = 9,   t =  = 3 seconds.     ANSWER



(b)  The position (the current coordinate) is ANTI-DERIVATIVE of the speed, i.e.

         position  x =  = 9t - .


     The particle is again at its starting point when its position is zero

          position x = 0,  or  9t -  = 0,  or  27*t- t^3 = 0,   t*(27-t^2) = 0,

          t =  =  seconds = 5.196 second (approx.)     ANSWER


      The speed at this moment is the value of  v = 9 - t^2  at t = , i.e.

      v = 9 -  = 9 - 9*3 = 9 - 27 = -18 meters per second.     ANSWER


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