SOLUTION: I am trying to help my daughter with the following and an stuck. I need answers and the steps to get there Find zeros of: 2x^3 -12x^2

SOLUTION: I am trying to help my daughter with the following and an stuck. I need answers and the steps to get there Find zeros of: 2x^3 -12x^2 - 6x

Question 1153999: I am trying to help my daughter with the following and an stuck.
I need answers and the steps to get there
Find zeros of: 2x^3 -12x^2 - 6x
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find zeros of: 2x^3 -12x^2 - 6x
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2x^3 -12x^2 - 6x = 2x*(x^2 - 6x - 3)
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Either 2x = 0 or (x^2 - 6x - 3) = 0
2x = 0 --> x = 0
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x^2 - 6x - 3 cannot be factored. Use the quadratic equation or complete the square.
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(x^2 - 6x - 3) = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=48 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6.46410161513775, -0.464101615137754. Here's your graph:

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I can do completing the square if you like.
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x^2 - 6x - 3 = 0
x^2 - 6x = 3
x^2 - 6x + 9 = 3+9 = 12
(x-3)^2 = 12

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You can sub that if you like.

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