SOLUTION: Find the equation of the circle with center at (6,3) and passes through the point (-6,-1)

Question 1153880: Find the equation of the circle with center at (6,3) and passes through the point (-6,-1)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Do what you can from that.

---MORE DETAIL----
Basic equation for circle in coordinate plane:
r is the radius.
point (h,k) is center point of circle.

Your given center is (6,3).
Point on circle is given as (-6,-1).

Left member of equation you want is .
Use the given point ON the circle to find the value of , the right member of the equation.

AND DO THE NECESSARY COMPUTATION to get this value for ;

Finished equation is .
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

<---> center (h,k), radius r

Example: center (3,-2) and radius 5 -->

Example: --> center (-1,4), radius 4

You are given the center (h,k).

The radius r is the distance from the center to the other given point. Use the distance formula (AKA Pythagorean Theorem) to determine r.

Then plug your h, k, and r in the formula.

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