SOLUTION: A particle moves along a horizontal coordinate line so that its position at time 𝑡 is given by 𝑥(𝑡) = 2𝑡^2 − 12𝑡. For what value(s) of 𝑡 is the particle at rest

Question 1147471: A particle moves along a horizontal coordinate line so that its position at time 𝑡 is given by 𝑥(𝑡) = 2𝑡^2 − 12𝑡. For what value(s) of 𝑡 is the particle at rest?
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
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Find the velocity (the speed) as the derivative of the position function over time


    v(t) =  = 4t - 12.


Equate it to zero and find the time moment when the speed is zero :


    4t - 12 = 0,


which gives you the answer for unknown time


     t =  = 3  units of time.    ANSWER

Solved and explained in all details.

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