SOLUTION: Two particles move along a coordinate line. At the end of t seconds their directed distances from the origin, in feet, are given by 𝑠˅1 = 4𝑡 − 3𝑡^2 and 𝑠˅2 = 𝑡^

Question 1147470: Two particles move along a coordinate line. At the end of t seconds their directed distances from the origin, in feet, are given by 𝑠˅1 = 4𝑡 − 3𝑡^2
and 𝑠˅2 = 𝑡^2 − 2𝑡. When do they have the same velocity?
Answer by ikleyn(52780) (Show Source): You can put this solution on YOUR website!
.


Velocity is the first derivative of the coordinate function over time.


For the first  particle, velocity is   = 4 - 6t.


For the second particle, velocity is   = 2t - 2.


Two particles have the same velocity when   = ,   or


    4 - 6t = 2t - 2.


From this equation find "t".


It will be your answer.

Happy learning (!)

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