# SOLUTION: Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina?

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 Click here to see ALL problems on Equations Question 114675: Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina?Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website!Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina? ---------------- Marina DATA: Rate = 24 mph ; Time = x hrs ; Distance = rt = 24x miles ------------------------- John DATA: Rate = 48 mph ; Time = x-2 hrs ; Distance = rt = 48(x-2) miles --------------------- EQUATION: distance = distance 24x = 48(x-2) x = 2(x-2) x = 4 hrs (Marina's Time) ------------------- 9AM + 4 hrs = 1PM ====================== Cheers, Stan H.